Masters Cup 12.11-19.11.2006

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14. studenog 2006. u 19:25

Defending champion David Nalbandian of Argentina and Ivan Ljubicic struggled into Wednesday morning before the Croatian profitted from a late break to produce a 5-7, 7-6 (9-7) 7-5 win.

Ivan Ljubicic's 30 aces in his three-set win was the most in a Tennis Masters Cup match since 1996 when countryman Goran Ivanisevic fired 35 aces in his 6-7, 7-6, 7-5 loss to Pete Sampras in the ATP World Championships semifinals.

The drama was nonstop, with Nalbandian suffering his second Red group loss in as many matches. He failed to serve out a straight-sets victory at 5-4 in the second set.

Ljubicic, who underwent a blood test on Monday after fighting a virus in recent weeks, was given the all-clear by doctors. The Croatian tested himself to the limit in two hours, 48 minutes.

In addition to this 30 aces, Ljubicic also fired 61 winners and struck 44 unforced errors while breaking Nalbandian three times.

Nalbandian was unable to bounce back from a defeat against Roger Federer in his opening round-robin match in China.

Ljubicic won his 60th match of the season as he played in the Tennis Masters Cup for the second year.

The 27-year-old with three titles in 2006 was unable to compete in the last two weeks of the regular ATP season due to his illness and the fatigue of a long season.

The Red group has yet to be settled with the mathematics still giving all four players in the group a chance to reach the semifinals.  
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14. studenog 2006. u 19:26
Iduci je napisao/la:
The Red group has yet to be settled with the mathematics still giving all four players in the group a chance to reach the semifinals.  
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Obrisan korisnik
Obrisan korisnik
Pristupio: 30.03.2006.
Poruka: 2.221
14. studenog 2006. u 19:29
Iduci je napisao/la:
Ancient Mariner je napisao/la:
Nasao sam:

c) Head-to-head results
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Za mene je to - ako Ljubo i Federer imaju po 2 pobjede, te 1 poraz, prvo se gleda Head-to-head.
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Problem je sto Rodick pobjedom ulazi u taj krug.
Obrisan korisnik
Obrisan korisnik
Pristupio: 10.09.2006.
Poruka: 6.000
14. studenog 2006. u 19:31

Evo me ponovo!

Čestitke Ljubi i pjuc Federeru!

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14. studenog 2006. u 19:32
A. Federer def. Ljubicic

1. Federer def. Ljubicic, Roddick def. Nalbandian

Federer 1st
Roddick 2nd

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2.1 Federer def. Ljubicic in two sets, Nalbandian def. Roddick in two sets

Federer 1st
Nalbandian 2nd

2.2 Federer def. Ljubicic in two sets, Nalbandian def. Roddick in three sets

Federer 1st
Nalbandian 2nd (tied in sets w/l with Roddick, ahead because of winning direct match)

2.3 Federer def. Ljubicic in three sets, Nalbandian def. Roddick in two sets

Federer 1st
Nalbandian 2nd

2.4 Federer def. Ljubicic in three sets, Nalbandian def. Roddick in three sets

Federer 1st
Games w/l decide about 2nd position between NLjubicic, Nalbandian and Roddick

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B. Ljubicic def. Federer

1. Ljubicic def. Federer, Nalbandian def. Roddick

Ljubicic 1st
Federer 2nd

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2.1 Ljubicic def. Federer in two sets, Roddick def. Nalbandian in two sets

Roddick 1st
Ljubicic 2nd

2.2 Ljubicic def. Federer in two sets, Roddick def. Nalbandian in three sets

Ljubicic 1st
Roddick 2nd

2.3 Ljubicic def. Federer in three sets, Roddick def. Nalbandian in two sets

Roddick 1st
Ljubicic 2nd (tied in sets w/l with Federer, ahead because of winning direct match)

2.4 Ljubicic def. Federer in three sets, Roddick def. Nalbandian in three sets

Games w/l decide about 1st and 2nd position between Federer, Roddick and Ljubicic  
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Obrisan korisnik
Obrisan korisnik
Pristupio: 30.12.2005.
Poruka: 3.660
14. studenog 2006. u 19:34
Ancient Mariner je napisao/la:
Nasao sam:

3) The final standings of each group shall be determined by the first of the following methods that apply:
a) Greatest number of wins;
b) Greatest number of matches played;
c) Head-to-head results if only two (2) players are tied, or if three (3) players are tied, then:
i) If three (3) players each have one win, a player having played less than all three (3) matches is automatically eliminated and the player advancing to the Single Elimination competition is the winner of the match-up of the two (2) players tied with 1-2 records; or
ii) Highest percentage of sets won; or
iii) Highest percentage of games won.
iv) If (i), (ii) or (iii) produce one superior player (first place), or one inferior player (third place), and the two remaining players are tied, the tie between those two players shall be broken by head-to-head record.
4) If ties still exist after the above procedures, the Steering Committee shall make the final determination. 
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Ako Nalby dobije Roddicka a Ljubo Fedju tada je jasno 1. Ljubo 2. Fedjo
 Roddick - Nalby 2-1 i Ljubo - Fedjo 2-0 1. Ljubo 2.Roddick
 Roddick - Nalby 2-0 i Ljubo - Fedjo 2-0 1. Roddick 2. Ljubo
Ovo tri pozitivne kombinacije za Ljubu

Roddick- Nalby 2-1 i Ljubo Fedjo 2-1 tada  tada Ljubo Roddick i Fedjo imaju po 2-1 i 5-4 u setovima, ali po pravilima iii) i iv) 1.Fedjo 2. Roddick
Najgora teorija za Ljubu po kojoj i sa pobjedom ispada

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14. studenog 2006. u 19:35
Najgore sto se moze znaci dogoditi je da Ljubo dobije u 3 seta, Roddick u 3. seta. Onda je svaki svakoga dobio: Ljubo>Federera, Federer>Roddicka, Roddick>Ljubu. E onda bi se gledali setovi....

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Obrisan korisnik
Obrisan korisnik
Pristupio: 30.03.2006.
Poruka: 2.221
14. studenog 2006. u 19:36
Iduci je napisao/la:
A. Federer def. Ljubicic

2.4 Federer def. Ljubicic in three sets, Nalbandian def. Roddick in three sets

Federer 1st
Games w/l decide about 2nd position between NLjubicic, Nalbandian and Roddick
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Ovdje Ljubo nema sanse.  Nalbi ce sigurno imati bolji omjer gameova. Za sada njihov krug je

Rodick      18-12
Ljubo       31-36
Nalbandian  18-19
Kauboj
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Većinski vlasnik Foruma
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Poruka: 22.210
14. studenog 2006. u 19:37
Ja glasam za opciju B.2.1. 
I am going to space, and when I come back I have to pick up poodle crap.
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14. studenog 2006. u 19:39
Ali to sve ako Ljubo dobije...a ako izgubi, onda pakuj stvari.
 
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