shankly je napisao/la:
A sto se desi ako 3 ekipe imaju isti omjer kome ide 1 pick
Vidi cijeli citat
Strength of schedule bi odlucila ako nisu medjusobno igrali. U tome su trenutno Coltsi u prednosti. Evo ti sa ESPN.
The suddenly surging
Indianapolis Colts are guaranteed to have the No. 1 overall draft pick should they lose their final game of the season.
The Colts started 0-13 but their second straight win was a stunner, 19-16 over the AFC South champion Houston Texans on Thursday.
Still,
if Indianapolis loses at Jacksonville on Jan. 1, they would finish with
at least a share of the league's worst record at 2-14 and have the top
pick in the draft by virtue of strength-of-schedule tiebreaker.
Both
St. Louis and Minnesota are 2-12 heading into Saturday's games, but the
Colts' .547 strength-of-schedule percentage is going to only worsen
after playing the 4-10 Jaguars. The Rams' percentage is .587 and the Vikings' .587.
If
the Colts beat Jacksonville and the Rams and Vikings lose their last
two, the Colts would not get the top pick. If the Colts beat the Jags
and St. Louis and Minnesota also finish 3-13, the No. 1 pick would go to
the Colts.
Minnesota has games left at Washington (5-9) and at
home against Chicago (7-7), and St. Louis finishes at Pittsburgh (10-4)
and at home against San Francisco (11-3).
“Kam hit this tight end SO HARD, I swear I saw that TE’s soul leave Qwest Field right on that 35 yard line.”